Recent content by Simply Is

I'm designing a 2-stage gearbox for a project at school (15:1 ratio, must transmit 20 hp, for a full-time 10-year minimum life). I've come up with 2 basic gear combos for my layout: 1. 16,80,24,72 2. 16,80,16,48 I've done all the calculations for each layout such as making sure that the...

Homework Statement 3.0 kg object is moving in plane with x and y coordinates given by x=5t^2-1 and y=3t^2-2 where x and y are meters and t is seconds. Find magnitued of net force acting on object at t=2 seconds. Homework Equations (vectors above the letters where they normally go)...

Whoops, that actually would not be the right way to calculate that angle of difference that it is out of level. I would have to know the length of the machine and use it as a "radius"... then calculate it that way, wouldn't I? And of course I have no measurement for the length of the...

Wait no... the formula is + 1/2 gt^2... and your gravity (g is basically the same for the y direction as a is in the x direction of your initial equation) is in the negative direction... so you would end up with an equation 0=115 + 5.1t - 4.9t^2... Then you'll have the right answer.

You box is traveling down... not up... and if you made toward the Earth be the negative direction, then you have to put a negative direction as your final displacement... which will give you positive 115 when you move it to the other side of the equation before you plug it into the quadratic...

Your question isn't asking you for the time... It is asking for the acceleration as a function of time... Function tells you that your answer will be an equation... not solution of the variable you have left. Go back to what you have before you solved for t.

What are you looking for? Is what you are looking for one of the variables you have left in the equation? If so, solve the equation. What does the variable you show there stand for? Is that what you are looking for?

Here's a hint... you can find how to come up with your answer online... It requires BASIC calculus to solve... Search for how velocity is related to displacement... then search how acceleration is related to velocity... It will tell you what you need to do to the equation you've got to get the...

The "u" stands for the initial vertical velocity (or in the case of not being directly straight up... the vertical component of the initial velocity). The "g" does stand for the gravitational constant of the Earth. It will probably help if you just draw a cartesian grid, label your x and...

Okay, I'm back... break time is over... I'm so excited! And in looking at this further, I can actually average the gravities that I came up with, and the opposing constant accelerations... coming up with 2 vectors right? Then if I set these vectors at 90 degrees from each other (1 in 1st...

Thank you so much, I thought my partners tested it with the level we had, but they may have just looked at it too quick and it was actually out of level. That would explain how I am coming up with an opposite constant acceleration, and one that is SO close to gravity... The device wasn't...

Hi there, I'm not sure if I'm posting in the right place or not... So please forgive if I am. I did an experiment today on Uniformly Accelerated Linear Motion. We used an Atwood's type machine that used pressurized air to reduce friction. We also used photogates to time the movement of the...