Recent content by skateza

Homework Statement I need to find the length of \frac{\frac{1}{3}x^{3} + x^{2} + x + 1}{4x+4} from x=0 to x=2 but i can not factor this down to be able to set up the integral, any suggestions, here is the derivative: \frac{\frac{8}{3}x^{3}+8x^{2}+8x}{16x^{2}+32x+16} It is possible I might...

Homework Statement Determine the magnitude of force F so that the resultant Fr of the three forces is as small as possible. What is the minimum magnitude of Fr? Homework Equations Their is a 5N force heading horizontally to the right, a 4 N force heading vertically downwards, Force F...

is this what you simplified it down to: \sqrt{(1/9)r^2[1-\pi^2r^4]}. If so, i got as a derivative: (1/2)[(1/9)r^2(1-\pi^2r^4)]^(-1/2) [(1/9)r^2(-4\pi r^3) + (1-\pi^2r^4)(2/9)\pi] which doesn't simplify down much nicer...

Homework Statement The volume of a right circular cone is V = [(pie)(r^2)(h)]/3 and it ssurface area is S = (pie)(r)(r^2+h^2)^(1/2), where r is the base radius and h is the height of the cone. Find the dimensions of the cone with surface area 1 and maximum volume. The Attempt at a Solution...

Okay i think i got it, is this right: Drawing a side diagram with a triangle and a rectangle in the middle i can use similar triangles to show cos(Theta) = h/(3-r) = 1; therefore h = 3-r Using this i get a maximum value of 4pie

okay with that i still can't figure out my peoblem. Here is the question i am really trying to solve. A right cirular cylinder is inscribed in a cone with height 3m, and base radius 3m. Find the largest possible volume of such a cylinder. V = (pie)r^2h, how would i find the height in this...

Homework Statement Find the volume of a right circular cylinder of maximum volume that can be inscribed in a sphere of radius 10cm. I'm using this problem to help me solve a similar one with a cylinder inside a cone, now what I'm not sure about is, in the answer book they say, Let the...

my error was in using the quadratic formula, i took -a instead of -b which is why i got a strange value.

Homework Statement Find the area of the largest rectangle that can be inscribed in the region bounded by the graph of y = (4-x)/(2+x) and the coordinate aces in the first quadrant. I think my only problem with this one is taking the derivative, this is what i get y' = (-x^2 - 4x +...

bump?

Ok i did that and i got as an answer F = (3F/2) + \mu_{s}Mg is that right? (I'm trying to think through this verbally here:) I can't see how its possible for a force to depend on the force itself?... or can i re-arrange the formula and than i would get: F = (-2 \mu_{s}Mg) But why...

so are you saying i would use: \alpha = LF/I = LF/(1/3)ML^{2} than a= \alpha L than F = m[ \alpha L + \mu_{s}g]

A rod of mass M rests vertically on the floor, held in place by static friction. IF the coefficient of static friction is \mu_{s}, find the maximum force F that can be applied to the rod at its midpoint before it slips. I'm not exactly sure what i am suppose to be looking for.. Obviously...

A thin, unirform rod (I=1/3ML^2) of length L and mass M is pivoted about one end. A small metal ball of mass m=2M is attached to the road a distance d from the pivot. The rod and ball are realeased from rest in a horizontal position and allowed to swing downward without friction or air...

i was being sarcastic, of course that's the first thing i did... i think on the bottom of my last post i meant to put f(a+x) = 6^x, and f(a) = 1 Therefore, f(x) = 6^x - 1 if you stuff a in for x, to get f(a), you get it f(a) = 6^x - 1 Since f(a) = 1 1 = 6^x -1 6^x = 2 do a log to find...