Recent content by skibidi

If anyone else sees this, can you verify that my explanation is correct since I was able to get the correct answers on my own.

Use I3 to get I2 and I1 since you have separate equations for them already - I1 = -3.4(I3)+14/5.3 and I2 = 3.4(I3) +16/ 8.2 I1 = 2.43 A , I2 = 2.09 A

Correction for the problem after i found I3 correctly now. The correct equation is now -14+3.3(I1)+3.4(I3)+2(I1)= 0 for the upper loop and -16+5.3(I2)-3.4(I3)+2.9(I2) = 0 for the bottom loop. Once you separate variables, I2 = stuff and I1 = stuff, you can use the junction rule I1 = I2+I3 and...

I separated the circuit into parts- upper and lower For the upper loop I wrote: -14-2I1-3.4I3-I2 = 0 For the lower loop I wrote 16-2.9I2+3.4I3-5.4I2 = 0 I solved for I1 and I2 separately and plugged it into the junction rule and solved for I3. I may have got it wrong because of the...

I hate this so much...

So would t be the duration since 0.5s, Some t value - 0.5s Let's say that I had to find the current at 1.1s, so would use the equation and substitute t for 0.6s. Would it be either I = 4.09A(1-e^(-1.1s/(L/R)) or I = 4.09A(1-e^(-0.6s/(L/R)) The second one was correct

0.5

Would I use the equation I used to solve for the current at a given time such as 1s.

I found that to be the maximum current

I found the time constant using L/R and got 0.62s (3.6H/5.8ohms) I found the initial current V/R and got 4.086A (23.7V/5.8ohms) I(f) = 4.086A(1-e^(-0.5s/0.62s)) Then I plugged it into the equation and got 2.26A and it was wrong