Recent content by skinard360

I figured it out, thank you!

n_1 moles of a monatomic gas and n_2 moles of a diatomic gas are mixed together in a container. Derive an expression for the molar specific heat at constant volume of the mixture. c sub v = 3/2 R for a monatomic gas 5/2 R for a diatomic gas thermal energy for a monatomic...

but I know the initial pressure is 1.097 atm

I'm not sure what the answer is...sorry

I tried another equation to get the final temp...thermal energy = 375 = (3/2)NkBT...then plugged it into pv=nRT but this didn't work either For the work equation above, does work = 375? I feel like I'm getting more confused the further I go

that would be the thermal energy, right? 375 J...did I use the right equation above with E=ncdeltaT with c=20.8 ? or should it be another equation, since that equation is assuming that the pressure in the system stays constant

that should just be 100 cm squared. I'm not sure what the significance is of container A is either...it may have to do with question (a) which asked which container would have the higher final temp. Do you think container A should have some part in the answer?

Two 800\; cm^3 containers hold identical amounts of a monatomic gas at 20^\circ C. Container A is rigid. Container B has a 100\; cm^2 piston with a mass of 10 kg that can slide up and down vertically without friction. Both containers are placed on identical heaters and heated for equal amounts...

ok...I got the answer...thanks :)

p = (w/A) + p(atmosphere) p = (98/.01) + 101,300 the answer is in Pascals

Two 800\; cm^3 containers hold identical amounts of a monatomic gas at 20^\circ C. Container A is rigid. Container B has a 100\; cm^2 piston with a mass of 10 kg that can slide up and down vertically without friction. Both containers are placed on identical heaters and heated for equal amounts...

you are right! thank you :)

i wasn't doing that, but once I tried it my answer was still wrong...here is exactly what I'm doing: [arcsin (1.55 sin 27)/1.5] - [arcsin (1.52 sin 27)/1.5] = .587 degrees

I tried it in degrees and got .014 but it was wrong :(

Homework Statement A sheet of glass has n_red=1.52 and n_violet=1.55. A narrow beam of white light is incident on the glass at 27.0 degrees What is the angular spread of the light inside the glass? Homework Equations Snells Law: theta2 = arc sin (n1 sin theta1)/n2 The Attempt at a...