What is the Molar Specific Heat of a Monatomic and Diatomic Gas Mixture?

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The discussion focuses on deriving the expression for the molar specific heat at constant volume for a mixture of monatomic and diatomic gases. The specific heat for a monatomic gas is 3/2 R, while for a diatomic gas it is 5/2 R. The thermal energy equations for both types of gases are provided, leading to the heat required for the mixture at constant volume. A user expresses difficulty in formulating the correct equation but ultimately resolves their confusion regarding the definition of molar specific heat. The conversation highlights the importance of understanding the contributions of each gas type in the mixture to calculate the overall specific heat.
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n_1 moles of a monatomic gas and n_2 moles of a diatomic gas are mixed together in a container.
Derive an expression for the molar specific heat at constant volume of the mixture.

c sub v = 3/2 R for a monatomic gas
5/2 R for a diatomic gas

thermal energy for a monatomic gas = 3/2 NkT = 3/2 nRT
diatomic Eth = 5/2 NkT = 5/2 nRT

c = J/molK, R = J/molK, n = mol

I started off by looking at the units and figuring that I needed to divide the n's somehow and multiply that times R...but I have tried many equations and can't seem to find one that works, and I can't figure out logically how that would work out...does anyone have any ideas?? I'm desperate
 
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If the temperature of the mixture is to be raised by dT the heat required (at constant volume) will be

n1(3R/2)*dT + n2(5R/2)*dT

Now what is the definition of molar specific heat?
 
I figured it out, thank you!
 
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