Recent content by skook

Think it's f(z)= (z-A+r)/(z-A-r) where both A and r are real numbers. The line has inverse points lying either side of it and mirrored by it. The unit circle has its centre and inf as inverse points. So you can map the A-r to the centre of the circle and A+r to infinity, then scale the circle to...

To try and sum up: 1) Cancel z top and bottom to show that the bottom term -> 1 as z -> 0. So that would remove the singularity and make the function analytic at zero. 1a) Because the bottom can't go to zero, the function must -> 0 when z -> 0. So there is a zero of the function at z = 0. 2)...

Log is analytic at zero when it is represented by a Taylor series about -1.

Thanks for that...the nearest I can get is that it could be 1/(2*pi) of a Dirac delta function with a pi/2 twist. :-)

Just spent the last few months working on an undergrad course in complex analysis and have a couple of things that aren't clear to me yet. One of them is the meanings of the residue of a complex function. I understand how to find it from the Laurent series and using a couple of other rules and I...

Got it Multiply both sides by (2-x)^2 and then factorise to get solution x \in (- \infty, \frac{8}{5}) \bigcup (2,\infty) . thanks skook

Could someone tell me how to find the solution set for the following, please. \frac{x}{2-x}<4 thanks skook

Have a look at Lyx.

I can do it, but can't understand how it works. Is there a straightforward expalnation in terms of \ \mathbb{Z}_{n} the set of remainers in modulo n? Could someone try to explain, pls.

Guess I was staring at it too hard. thanks

Could someone please point me forwards again. By integrating the following equation twice... \frac{1}{x^2}\frac{d}{dy}(x^2 \frac{dx}{dy}) = 0 I tried integrating by parts but came to a sticky end. many thanks skook

:rolleyes: I am trying to learn how to use the AMSMATH package. Can anyone tell me how to change the size of \sum to make it bigger? thanks

thanks for that I hope the solution is y=-\frac{x}{\ln{Cx}}. It was from an Open University course (http://www3.open.ac.uk/courses/bin/p12.dll?C02MS324) . First maths course I've done in over 25 years...

Could someone please just give me a hint to get started. \frac{dy}{dx}-\frac{y}{x}=\frac{y^2}{x^2} for x>0 thanks Skook