Recent content by Skotster

sorry about the typo forgetting to add the "^2" after t in my equations

i'm assuming you mean parellel plates as capacitors and uniform electric fields. you need: three quasions of kinamatics a=F/m E=F/q

you could use theta in terms of n like this theta=20+5n where n is a whole number between 0 and 10 use your basic algebra to substitute in variables, ie: the for t in dx=Vix*t put dx=Vix*-2Viy/(-9.8m/s^2) do the same for Vix and Viy, and then again for theta. SN: PBGartist (aim)...

break up your Vi=100m/s at 20 degrees into the x&y components Vix=Vi*cos(20 degrees) Viy=Vi*sin(20 degrees) assuming you are on Earth and ingoring air friction use Vf=Vi+(-9.8m/s^2)*t to get t=(Vf-Vi)/(-9.8m/s^2) lettin Vf=0 to find time to max height double it to get the total...

Second one: Protons are projected at an angle of 300 with an initial speed, given by V0=8.2*105 m/s, in a region of an electric field E=-390j N/C, is present. The proton is to hit a point 1.27 mm in the pos-x direction from the launch point. Find (a) the two porjections angles (theta) that...

V=V0+a*t d=V0*+(1/2)*a*t V2=V02+2*a*d V=Final velocity V0=Initial Velocity d=Distance a=Acceleration t=time

Thanks much

Am I interpreting this question correctly? So, does that mean: Vector A=8 at 45 degrees Vector B=8 at 180 degrees or Vector A=8 at 45 degrees Vector B=8 at 225 degrees I know how to do the problem, it's just interpreting the book's wording on angles. Thanks