# 2 challenge problems for tommorrow(dec 7)

1. Dec 6, 2004

### Skotster

Second one:
Protons are projected at an angle of 300 with an initial speed, given by V0=8.2*105 m/s, in a region of an electric field E=-390j N/C, is present. The proton is to hit a point 1.27 mm in the pos-x direction from the launch point. Find (a) the two porjections angles (theta) that will result in a hit, and (b) the total time of flight for each of these two trajectories.

Here is what I can get for this one.
(theta)=cos-1(V0x/V0)
(theta)=sin-1(V0y/V0)
F=q*E=-1.15*10-16 N
a=F/m=-6.89*1010 m/s2

First one: Solved
on an analogue clock the minute hand aligns perfectly with the hour hand once and hour. 12:00 is the first time, when are the exact other times this happens. (Hint: in only happens 11 times, not 12 and the hour and minute hand constantly move)

time=3927.272727s*n
where n is the number of times the min hand has ligned up with the hour hand
ex:
1st time...........1:05:27.2727

Last edited: Dec 6, 2004
2. Dec 6, 2004

### Tide

re: the first one

The hands will coincide every $\frac {12}{11}$ hours. Just convert that to hours, minutes and seconds.