Recent content by sleepymia

Ah I understand now, thank you!

Horizontal distance = (L/2)cos(22.6) Vertical distance = (L/2)sin(22.6) + (L/2) Edit: so torque from spring would be the perpendicular force of the spring in relation to the beam multiplied by the horizontal distance I found?

You're right it is at rest, my bad just not horizontal. In diagram the spring length I think would be (L/2)+x Corrected torque of spring kx(L/2)sin(Φ), where Φ is the angle labeled in the drawing below

Yes I am defining x as extension of the spring, and the spring is at a non-right angle to the beam and not vertical since it is not at rest.

Homework Statement Consider a rigid 2.60-m-long beam (see figure) that is supported by a fixed 1.30-m-high post through its center and pivots on a frictionless bearing at its center atop the vertical 1.30-m-high post. One end of the beam is connected to the floor by a spring that has a force...