Recent content by Sligh

Got it. Thanks a lot!

Ah, you are correct. Then I must add the radius of the Earth plus the distance at which the astronaut is above the Earth, yes? Here's my new results: F = 6.67E-11*(81.632)(5.9742E24) / (6.37E6 + 6378.1)^2 F = 800.0514292 N W = 81.63790094 kg Is that it? Thanks.

Thanks for the assistance. Here's what I figured -> F = 6.67E-11*(81.632kg)(5.9742E24kg) / (6.37E6)^2 F=801.624N W=81.8014kg Is this alright? Thanks!

Homework Statement An astronaut weighs 800 N on the surface of the Earth. What is the weight of the astronaut 6.37*10^6 km above the surface of the earth? Homework Equations F = G (m1)(m2)/(d)^2 W=ma The Attempt at a Solution I am sure that I need the previous equations I...

Ah, yes! This is exactly the piece of the puzzle I was missing. I had that written on my free body diagram; I haven't the faintest idea why I overlooked it! Many thanks!

I thought about what you wrote and this is what I have figured: \SigmaF = 9 - 0 = 4(acceleration) acceleration = 4/9 m/s/s (final velocity)^2 = (initial velocity)^2 + 2(acceleration)(distance) (9)^2 = (0)^2 + (2)(4/9)d d=91.125 m ____ However, I am almost certainly incorrect...

There is a picture; apologies for not describing it previously. There is an incline of 35 degrees with a box of 4.0kg almost to the end of it. The box was previously up the incline quite a bit (distance "d") as indicated by a box with broken lines. Apologies for not providing a picture. Is...

A 4.0 kg block has a speed of 9.00 m/s at X. What is the maximum distance, d, traveled by the block. Ignore friction. There is a angle of 35 degrees. ___ I know this a very simple problem, and I have solved problems similar to this in my honors physics class; however, I have not solved...

Thanks anyhow. I figured it out now. ;)

Homework Statement The 68 kg climber in Fig. 4-52 is supported in the "chimney" by the friction forces exerted on his shoes and back. The static coefficients of friction between his shoes and the wall, and between his back and the wall, are 0.78 and 0.55, respectively. What is the minimum...