Sligh said:Thanks for the assistance. Here's what I figured ->
F = 6.67E-11*(81.632kg)(5.9742E24kg) / (6.37E6)^2
Sligh said:Ah, you are correct. Then I must add the radius of the Earth plus the distance at which the astronaut is above the Earth, yes?
Here's my new results:
F = 6.67E-11*(81.632)(5.9742E24) / (6.37E6 + 6378.1)^2
Weight above the surface of the Earth refers to the force exerted by an object due to the Earth's gravity. It is the result of the mass of the object and the acceleration due to gravity, which is approximately 9.8 meters per second squared near the Earth's surface.
The weight on the surface of the Earth is the force exerted by the Earth's gravity on an object when it is in direct contact with the surface. Weight above the surface, on the other hand, takes into account the distance between the object and the surface, which can affect the strength of the gravitational force.
Yes, weight above the surface of the Earth changes at different altitudes. This is because the distance between the object and the center of the Earth changes as altitude increases, and therefore the strength of the gravitational force changes as well.
The weight above the surface of a planet is dependent on its mass and the strength of its gravitational force. Therefore, weight above the surface of other planets will vary based on their size and density. For example, an object that weighs 100 pounds on Earth would weigh 38 pounds on Mars due to its lower gravitational force.
No, weight above the surface of the Earth cannot be negative. Weight is a measure of the force of gravity, and gravity can only pull objects towards the center of the Earth. Therefore, weight will always be a positive value, even if an object is in free fall above the Earth's surface.