Recent content by smally

Oh right, the "he's being pushed into his seat 8.5 times more force than normal" got lightbulb above my head appear then thanks. and for b) r = 95.83^2 / (9.81 x 8.5) r = 110.13 correct, thank you

Ok so I've now done: 50 x 9.81 x 8.5 = 4169.25 50 x 9.81 = 490.5 4169.25 + 490.5 = 4659.75 but I'm a bit confused as to why I times gravity for when working out Fcent. I also assumed that the answer to a, would help me with b; but I'm still getting the answer wrong

[SOLVED] Uniform circular motion problems Homework Statement A pilot of mass 50kg comes out of a vertical dive in a circular arc such that his upward acceleration is 8.5g Homework Equations a) What is the magnitude of the force exerted by the airplane seat on the pilot at the bottom of...

Ok I've now come across a new question where my answers are different to the answers given: 11. Two blocks attached by a string slide down a 20o slope. The lower block has mass m1=0.25kg and coefficient of kinetic friction 0.2. The upper block has mass m2=0.8kg and coefficient of kinetic...

Thats wonderful, I've finally done it, Thank You all very much.

Silly me, I overlooked that, thank you. I think I've now done question 2 correctly now. 2a) ma = \mu_{s}g a = 0.5 \times 9.8 a = 4.9 so \Delta x = 91.84 2b) ma = \mu_{k}g a = 0.3 \times 9.8g a = 2.94 so \Delta x = 153.06 however the answer given for 2b is...

Oh ok :D, I've managed to now get this: ma = \mu_{s}mg a = \mu_{s}g a = 0.3 \times 9.8 a = 2.94 therefore: \Delta x = \frac{v^{2} - v^{2}_{0}}{2a} \Delta x = \frac{0^{2} - 80^{2}}{2 \times 2.94} \Delta x = 1088.44 however the answer I am given is 83.7m, what have I doing...

Sorry I'm confused how you get to the point of cancelling m out I always get to this point: f_{s,max} = \mu_{s}F_{n} f_{s,max} = \mu_{s} w f_{s,max} = \mu_{s} mg f_{s,max} = \mu_{s} \frac{F}{a}g f_{s,max} = 0.3 \times 9.8\frac{F}{a} Since I don't have F or a; I get stuck...

Hi, this is my first post and I'm a bit rusty will mechanics so I need help with two questions I've come across Firstly on the question sheet I am given: a = F/m and w = mg and the static friction and kinetic friction equations also v^{2} = v^{2}_{0} + 2a\Deltax How do I do these...