Recent content by snaamlsa

lol yeah there was the real problem, I figured it out thanks a loooooooooooooooooooot! sorry for being an idiot :P

Ok I've got it Thanks guys especially fzero, you made me think and now I got the answer by myself thanks a lot for coming back everytime I really appreciate it ^__^

B.C = -3.2 Cx + 7.2 Cy is it here how should I substitute for Cx: -3.2 (1.34) + 7.2 Cy = 19 Cy = 3.2344 (which I know is wrong) A.C = 5.1 Cx - 6.7 Cy 5.1 Cx -6.7(3.2344) = 0 Cx = 4.2491 (which is wrong) lol I'm not good with Maths either :\

I've tried that but it doesn't seem to work x_X I think it's more of a mathematical problem than a physics one -.-

oh sorry, so here is my work: A.C = AxCx + AyCy 5.1Cx - 6.7Cy = 0 Cx = 1.34 Cy and here we're finished with A.C and will work on B.C = 19 with the value of Cx = 1.34 Cy . . . but how?!

thanks for the hint but it doesn't help -_- I'm really tired of trying to solve it and I'm kinda near giving up that's why I ended up here guys so that you could help me, so please do help! I want an answer with explanation :) this is what I got recently --> Cx = 1.34 Cy and then? I don't...

Homework Statement You are given vectors A = 5.1i - 6.7j and B = - 3.2i + 7.2j . A third vector C lies in the xy-plane. Vector C is perpendicular to vector A and the scalar product of C with B is 19.0 What're Cx and Cy? The attempt at a solution A.C = 0 B.C = 19