Recent content by snoopygal327

Okay, so I use the equation PV = (2/3)K. I assumed that the pressure is the standard 1 atm. Plugging everything into the equation: 101300 Pa (45 m3) = (2/3)K K = 6837750 J But the computer is telling me that this is the wrong answer. Did I do something wrong?

Homework Statement An empty room in a house near the Atlantic coast has a volume of 45m3. What is the kinetic energy of all of the gas molecules in the room on a 30C summer day? Homework Equations pv = nrt The Attempt at a Solution I realize that this is an ideal gas law problem, but I...

Oh I see. Thank you.

I have to calculate another impulse for the gravitational force? So it would be something like J = (1.5 kg)(9.8 m/s2)(.25s).

Homework Statement A ball of mass 1.5 kg is traveling downward at a speed of 10 m/s. It comes to rest in your hand in .25 s. What is the net impulse exerted on the ball? What is the average force exerted by the hand on the ball (Don't forget the gravitational force.) Homework Equations...

Thank you!

Oh so does that mean that after the block has accelerated, you only need to apply a force of 1.5 N to keep it moving at twice the constant velocity?

Okay, I remember now that friction force doesn't increase with velocity. In that case, pulling with a force of 3 N would cause acceleration. Then is it even possible to move the block with twice the constant velocity?

1) Homework Statement A force of 1.5 N is applied to a block on a flat surface and the block moves with a constant velocity. Approximately what applied force is needed to keep the block moving with a constant velocity that is twice as large as before? Homework Equations F = ma The...