Recent content by snowwhite

How to calculate the Work done in a isobaric process piston?

The exponent is 1.135 Sorry about that

Homework Statement Steam is raised as saturated steam at 6 bar (g) and supplied to the first ( high pressure ) piston. The steam then exhausts from piston 1 at 3 bar (g). The steam is thought to expand adiabatically in accordance with PV^( 135 .1)= Constant Given the initial volume is...

can u please provide me a web page to look at the specific volume of saturated liquid water at 9 MPa? or a good steam tables web page to look at it? I have books with steam tables, steam tables in pdf and really DOES NOT APPEAR LIQUID WATER. WHAT APPEARS ITS COMPRESSED WATER.?IS THAT IT?

b) USING THE STEAM TABLES P= 1 MPA, V= 0.264 Vactual=0.25790 Z=PVactual/RT=0.9744 SO: CONCLUSION: As seen the Ideal Gas Assumption is very good for this case. The water vapour is acting ideally

The IDEAL GAS LAW EQUATION: PV=nRT the pressure is always in PA or Kpa. I diveded by pressure to calculate the Volume Yes, the gas constant is in KJ/kg like I wroted it.

looking at the steam tables: at 90 atm= 9MPA specific saturated steam volume is =0.001418metres cube/kg In my steam tables does not appear saturated liquid water volme. How can I find it?

First, I convert the pressure given to bar. so: 9 atmx (1.01325bar)/1atm = 91.1925 bar I look these temperature in the steam table for specific volume of saturated steam and saturated liquid water, and these temperature does not appear. so I need to interpolate.How can I do it?

PV= nRT, V=nRT/P= (1 mol)(8.314 JK^-1mol^-1)(573.15 ºK)/(1000)= 4.76 metres cube 145 psi= 10^5 Pa x 10 = 10^6Pa= (10^3 KPa)=1000 KPa= pressure To calculate the molar volume of steam: For steam: R= R/M= (8.31434)/18=0.4619 KJ/KG hence: PV=nRT So V=RT/P=(0.4619)(300+273.15)/1000 KPa=0.264...

yes, of course. Ideal gas law equation: PV=nRTdeal gas law: PV= nRT so: V= nRT/P= (18 mol)(8.314 JK^-1mol^-1)(573.15 ºK) ( ) = 85773.04=8.5x10(^4) metres cube

The problem doesn´t mention if dry stream and liquid water are present together. The problem only provides me rate of pipe 100kg/s. The quality x=80 % =0.80 and the pressure= 90 atm. Determine the volumetric flows of dry steam and liquid water. do u know any formula to find the volumetric...

so how can I calculate the molar volume using the steam tables? and how can I know if the water vapour is acting ideally?

By the way, I always do everything different from everybody else that why I´m different

It doesn´t say. I think it will be gauge pressure units of steam tables? vg= metres cube/kg If u want to have a look, Steam tables attached By the way, I always do everything different from everybody else, that why I´m different

Steam flows down a pipe at a rate of 100kg/s. The steam flow has a quality of 80% at 90 atm. Determine the volumetric flows of dry steam and liquid water.