A car (m = 760 kg accelerates uniformly from rest up an inclined road which rises uniformly, to a height, h = 44 m. Find the net power the engine must deliver to reach a speed of 20.7 m/s at the top of the hill in 22.5s (NEGLECT frictional losses: air and rolling, ...)
I know that...
When mass M is at the position shown, it is sliding down the inclined part of a slide at a speed of 1.89 m/s. The mass stops a distance S2 = 1.85 m along the level part of the slide. The distance S1 = 1.25 m and the angle theta = 37.7 degrees. Calculate the coefficient of kinetic friction for...
How do I figure velocity?!
What is the velocity of the mass as it breaks contact with the spring?
From part 1 I got:
A 1.118 kg block is on a horizontal surface with mu-k = 0.150, and is in contact with a lightweight spring with a spring constant of 715 N/m which is compressed. Upon release...
Velocity from variable force(spring)?
What is the velocity of the mass as it breaks contact with the spring?
From part 1 I got:
A 1.118 kg block is on a horizontal surface with mu-k = 0.150, and is in contact with a lightweight spring with a spring constant of 715 N/m which is compressed...
Kinetic Energy, Help!
A 66.0 kg diver is 4.90 m above the water, falling at speed of 8.20 m/s. Calculate her kinetic energy as she hits the water. (Neglect air friction)
Then the problem hints:Use conservation of mechanical energy.
So I'm thinking that conservation is K_f+U_f=K_i+U_i but...
Here it is:
A) Energy conservation law for a projectile (no friction): Potential energy decrease equals the kinetic energy increase.
B) More power is required while slowly lifting a box than while lifting it up quickly.
C) Work cannot be done in the absence of motion.
D) Energy is required...
A 680.0 kg car traveling on a level road at 27.0 m/s (60.5 mi/hr) can stop, locking its wheels, in a distance of 61.0 m (200.1 ft). Find the size of the horizontal force which the car applies on the road while stopping.
Correct, computer gets: 4.06E+03 N
now:
Find the stopping distance...
A mass of 4.100 kg is suspended from a 1.430 m long string. It revolves in a horizontal circle.
The tangential speed of the mass is 2.899 m/s. Calculate the angle between the string and the vertical (in degrees).
I used the data I have, but either the formula I'm using is incorrect or I'm doing something wrong. I tried using a=V^2/2(d) and i tried to solve for d there but i don't get a correct answer. Can you recommend any formula for this maybe a variation of the 3rd law( i assume this is a 3rd law...
Actually this was a two part problem the first part was:
A 680.0 kg car traveling on a level road at 27.0 m/s (60.5 mi/hr) can stop, locking its wheels, in a distance of 61.0 m (200.1 ft). Find the size of the horizontal force which the car applies on the road while stopping.
The...
Question about Statics!
Hey I'm having trouble finding examples of statics in different engineerings.
See i ave this homework assignment where i have to look up an example problem of either computer or electrical engineering. The catch is that i have to find a problem related with statics...