How Do You Calculate the Coefficient of Kinetic Friction on an Inclined Plane?

AI Thread Summary
To calculate the coefficient of kinetic friction on an inclined plane, the discussion highlights the use of energy conservation principles, specifically the formula mu_k = (-1/2*(V_i^2) - 1/2*(g*h)) / (g*S_total). Participants note the importance of incorporating the incline angle, which affects the height calculation (h = S*sin(37.7)). There are concerns about the accuracy of the frictional force representation and the signs used in the calculations. Misunderstandings about the incline's impact on the overall energy balance are also pointed out. The conversation emphasizes the need for careful consideration of all forces and angles involved in the problem.
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When mass M is at the position shown, it is sliding down the inclined part of a slide at a speed of 1.89 m/s. The mass stops a distance S2 = 1.85 m along the level part of the slide. The distance S1 = 1.25 m and the angle theta = 37.7 degrees. Calculate the coefficient of kinetic friction for the mass on the surface.

Well i kinda found a formula for this by changing the conservatiion of energy(K_f+U_f=K_i+U_i+W_nc).

The formula is mu_k=(-1/2*(V_i^2)-1/2*(g*h))/(g*S_total),

But I still don't get the right answer am I doing something wrong?
 
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Think again:
You haven't used the information that you are on an INCLINED plane!
 
I used the incline plane to figure out h=Ssin37.7=0.26
 
It's still wrong, you've used a frictional force: \mu{mg}
This is incorrect.
In addition, your signs are messed up
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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