Recent content by songoku

I have checked, it is what I wrote. I understand. I suppose it would be half-cycle average Thank you very much Gordianus, pbuk, Steve4Physics

I know the formula of emf of generator is ##\varepsilon=NBA\omega \sin (\omega t)##. If I draw the graph of emf against time, the graph will be sinusoidal and if I find the average, the average will be zero. How can the average emf of generator is ##\frac{4NBA}{T}##? Thanks

Thank you very much haruspex and Orodruin

Is the answer 1? Because the cord is connected to vibrating source and it vibrates with a frequency of 100 Hz so section A and B have the same frequency Thanks

I understand. Thank you very much for all the help and explanation haruspex, apostolosdt, nasu, Steve4Physics, hutchphd

Is what in my notes incomplete? Because if the intensity increases, I also need to know about the frequency to be able to draw any conclusions about the saturation current. Thanks

What I understand so far is: For my 1st question ##\to## frequency is constant (presumably) but intensity increases so rate of photon increases For my 2nd question ##\to## frequency increases but intensity stays the same so rate of photon needs to decrease I have some other questions to clear...

From practice questions given by teacher, answer also given. The level of the question is high school. For 1st question, answer key is (D). For 2nd question, the answer is something like the photon per second will be lower so the photocurrent will decrease. This is what in my notes: So I am...

I have trouble understanding these two separate questions: I know the answer for this one, it is (D). The KE of electron depends on the frequency of the light so since the frequency of the light does not change (I assume so), the KE wil stay the same. Increasing the intensity will increase the...

Yes. I understand your hint. Thank you very much Orodruin

Is the reason related to post #2? And maybe also related to conservation of energy and momentum? Thanks

I am not really sure how to interpret the slope. The equation is: $$N=N_o e^{-\lambda t}$$ If the graph is N against t, then what is the slope? I can find the slope if the graph is log: $$log N=log N_o -\lambda t$$ So if the graph is log N against t, then the slope is ##-\lambda## But if...

Can the horizontal line be removed so the diagram only shows two lines (one for electron and one for positron) and two photons? Thanks

This is Feynman diagram of annihilation I get from wikipedia https://en.wikipedia.org/wiki/Annihilation I don't understand what the middle line with arrow to the right is. If I consider the left vertex and conservation of charge, it means the horizontal line with arrow to the right should carry...

I get it. It is actually related to the intensity of the sound wave, not to the frequency. The frequency is still consistent with Doppler effect formula. Thank you very much for the help and explanation haruspex, Orodruin, Steve4Physics