Recent content by soniccowflash

Okay..yes. The problem is that with my Y(s), there is a (s+1) and (s-1) in the denominator, but you have (s-1)^2. So I'm not sure how to get two (s-1)'s in the bottom of Y(s) because: sx(s) - x(0) - SY(s) - Y(0) + x(s) - Y(s) = 0 sx(s) -3 - SY(s) - 0 + x(s) - Y(s) = 0 x(s)(s+1) - Y(s)(s+1) =...

How did you know there was a mistake? And yup, our equations are the same.

Ok so I tried working with equations 1 and 2, here's what I got: sx(s) - x(0) - SY(s) - Y(0) + x(s) - Y(s) = 0 sx(s) -3 - SY(s) - 0 + x(s) - Y(s) = 0 x(s)(s+1) - Y(s)(s+1) = 3 x(s) = (3/s+1) + Y(s) This is where I put x(s) = (s-1)^-2 + (3/s-1) - 2Y(s) in. (1/(s-1)^2) + (3/s-1) - 2Y(s) =...

Yes, it is specifically asking to use the Laplace Transform, not algebraic systems. By using the Laplace Transform you do get an algebraic system though. At first I did make the mistake of looking at it in terms of algebra, but the answer looked very wrong. Not that bad of an idea though..just...

Somebody please help!

Hello. I have gotten as far as to use the Laplace equation with these formulas, but I am having difficulty getting y and x to relate to each other. If requested, I can post my work, but I am sure it is fraught with mistakes. Help is very much appreciated! x' + 2y' - x - 2y = e^t x' - y' + x...