Recent content by sonya

ok...now I'm really lost! I thought I made an equation from the given vector...so what do I do instead ?

OK...now I've thought about this...I should use the formula 1/(1+m2) [1 m ] ________[m m2] using 2x+5y = 0 my slope m = -2/5 but my numbers come out backwards ...

Find the matrix A of the orthogonal projection onto the line L in R2 that consists of all scalar multiples of the vector [2 5]T . OK...I really don't know how to start off with this problem. If somehow could just help me out there I will try to muddle my way through the rest ! Thanks.

Let P=(9,-7,-1) and Q=(-5,-5,-5). The set of all points that are equidistant from P and Q are given by the equation __x + __y + __z + __ = 0. ^^The question! All I want to know is how to start this question. I thought I was supposed to find the equation of the normal to the center of PQ...

I just had a quick thing i wanted to clarify... The question was: If u have two horizontal parallel current carrying wires 196 cm apart, with the bottom wire carrying a current of 2.2 A to the west and the top 1.1 A to the west, what is the magnetic field at the point P? Point P being the...

ok i got it...i was having problems with integrating but i figured it out...thx 4 all the help...much appreciated!

ok...im not gettin newhere with this problem...if ne1 has ne suggestions that would b awesome

yes...that was the formula i meant outandbeyond... and thanks 4 the help...now i jst have 2 factor that rite..

Find the length of the parametrized curve given by x(t)=0t3+9t2+36t y(t)=-1t3-6t2+15t for t between 0 and 1. ok...thats the question. I have tried using the formula L = integral of (dx/dt)2 + (dy/dt)2 all square rooted but I am not gettin the rite answer...i have a bunch of these...

oks...im having problems applying the mean value theorem...i understand the concept behind it but whenever i try 2 do a question i have no idea wat 2 do...heres 1 question I've been trying: Showing all your work, apply the Mean Value Theorem to show that the function arctan x - x is equal to...

but wouldn't that happen with ne bounce then...not jst the "perfect" one?

ok my physics class jst did a lab on studying rebound and last question in the report says: An extrapolation of the data to a perfect bounce (ie. one that reaches to the height of the launch point) results in a bounce distance that is more than twice the horizontal distance of the point of...

o..never mind that question...i get it now thx a lot!

ok..i think i understand now but a quick question where x = 3y -4 that can also be called f-1(y) rite?

if ur given a function f(x) and ur asked to find f^-1(y)...r u supposed 2 solve ur original eqn for y and then take the inverse of that? or isn't that just the same thing neways?...