Haha! :smile:None indeed BvU! As I said, it is just an inquiry I had with a friend of mine the other day. It surprised me that the only method I could find involved integration and then inversion of the result so I thought that I might be going down the wrong path. At best, there should be a...
Thank you for replying BvU! You are absolutely correct ##\dot{x}## is not the one I wrote but
$$\dot{x} = \sqrt{2g}\sqrt{\frac{e^{2x}-e^{x}}{e^{2x}+1}} = \sqrt{2g}\sqrt{\frac{1-e^{-x}}{1+e^{-2x}}}$$
I also noted that ##\dot{y}## needs a minus in order for ##\dot{y} = -e^{-x}\dot{x} = -y...
Homework Statement
I would like to ask a question I was discussing the other day with a friend of mine. Suppose you have a point mass m, sliding on the friction-free curve y = e^{-x} starting from position x(0) = 0 and y(0) = 1 with zero initial velocity. Can we find in closed-form the exact...