Recent content by sotownsend

Answer: The question wanted the integration of the final term of the derivation of the chain rule. So... ∫[(s^2 + 18s)/(6s+6)] = ∫(s^2 / (6s + 6) + ∫(18s / (6s + 6) The integral of these two terms yields a s^2 term with -1/12 as the coefficient. (Takes a lot of trig transforms /...

Homework Statement Find the coefficient on the x^2 term in ∫[(x+9)/3] * [log(x+1)] * dx Answer: -1/12 Homework Equations Integration by parts ∫dv * u = u * v - ∫du * v The Attempt at a Solution 1. I integrated by parts to get ------------------------- ∫[(x+9)/3] * [log(x+1)] * dx] =...