Answer:
The question wanted the integration of the final term of the derivation of the chain rule.
So...
∫[(s^2 + 18s)/(6s+6)] =
∫(s^2 / (6s + 6) + ∫(18s / (6s + 6)
The integral of these two terms yields a s^2 term with -1/12 as the coefficient. (Takes a lot of trig transforms /...
Homework Statement
Find the coefficient on the x^2 term in ∫[(x+9)/3] * [log(x+1)] * dx
Answer: -1/12
Homework Equations
Integration by parts
∫dv * u = u * v - ∫du * v
The Attempt at a Solution
1. I integrated by parts to get
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∫[(x+9)/3] * [log(x+1)] * dx] =...