Recent content by spaceman0x2a

Thanks. I just went and looked at this further and realized the mistake I was making - I thought it was the integral of acceleration with respect to time, when it was actually velocity (##at##) with respect to time. I feel really stupid now, but I guess this is how you learn.

And yes, I know this is similar to my previous post here.

Looking at s = ut + 1/2(at^2), the first part makes sense to me, but I am confused about the 1/2(at^2). I can see that this is the integral of acceleration with respect to time, but I don't understand why. Is this simply a coincidence? I know that this is considering a linearly rising...

Yes, this is what I wanted to confirm. Thankyou everyone for bearing with me on this, I didn't explain what I was thinking of very well.

I think I have an idea of this but I just want to be sure, and I also have some extra questions that I want to clear up. The work done on an object is the dot product of the force vector with the displacement vector, Fd*cos(theta). Am I correct in that this is without regard to velocity? i.e...

Hi! I'm a general STEM nerd from Tasmania, Aus. I have a particular interest in space related fields, especially aerospace engineering. I also do some electronics and hamradio things. Recently I've become interested in QM stuff, which I've known a basic amount about but have lacked a full...