Recent content by SpacemanRich

Ok. I have seen the error! Boy do I feel silly.:oops: My equation 3 should be ay = 1/2 ax I swear, I think my reading comprehension is just off sometimes. o_O Thanks a lot for the help, again. It is appreciated. :smile:

From the diagram?? Really, I never would have guessed that. I'll take another look and see what I can see. Just to check, if I can find the mistake in my eqn 3, will I get the answer the book has?? (13.7N, and 1.37m/s2) Also I'm glad my FBDs are ok. I thought that may be the source of my...

Ok, Thanks for the information. I'll do that in the future. I have my work scanned already. My work equations are numbered for reference. That should help this time. Thanks for taking a look.

Ok, I'll post a scan of my work as soon as I can get it scanned in. That will most likely be sometime tomorrow.

I'm sure my answer is pretty close. They give the answer as 13.7N and 1.37 m/s2. Also I found the acceleration for the 10kg mass to be 2 times as fast as the 3kg mass. (2ax = ay.) That is in line with there 2x = y hint.

I reworked the problem with your understanding of the meaning of "extra" information, and approaching it that way everything works out. Thanks for the help. Also, I have never encountered a problem where I had to apply information that way to solve the problem. It was very eye opening...

Homework Statement [/B]In the drawing, the rope and the pulleys are massless, and there is no friction. Find (a) the tension in the rope and (b) the acceleration of the 10.0-kg block. (Hint: The larger mass moves twice as far as the smaller mass.) 2. Formula's Used. F = ma, W = Mg. The...

Thanks. I agree. At least I know now I wasn't missing any obvious physics concept I should be learning. That is reassuring. Thanks again.

Ok, I'm going to start fresh with this new way of reading the problem. I'll be back after I give it a try. Thanks for your input.

If F is extremely large it would make mg too small to matter. But I don't think that a large F is a requirement to the solution, It seems more of a way to emphasize that the angle is the critical issue. That's the way it reads to me, anyway. Thoughts??

Yes, I'm familiar with the concept of a Limit. Unfortunately, I don't think that would be of any help here. This problem is from an Algebra based Intro to Physics text. Cutnell and Johnson, 9th edition to be exact. So, I think we are looking for an Algebra based solution.

That looks "Almost" the same as mine. The only difference is that I included a vector for the Weight of the box. That also seems to be where my problem came from. Can you tell me why you didn't include the weight of the box? I'm pretty certain that is my mistake. I just don't understand why...

That's the same answer I guessed at. But I still don't understand Why? It would help to see the FBD.

This seems to be on the right track. The answer (by guessing, and trial and error) looks to be ##\theta = tan^{-1}(1/\mu_k)##. The problem is I don't know why. Can you post your Free Body Diagram? I think that is where I made my mistake. Thanks.

The actual answer given is 68o