# Homework Help: Newton's second with Pullys, Ropes, and Boxes (Frictionless)

Tags:
1. Apr 27, 2015

### SpacemanRich

1. The problem statement, all variables and given/known data
In the drawing, the rope and the pulleys are massless, and there is no friction. Find (a) the tension in the rope and (b) the acceleration of the 10.0-kg block. (Hint: The larger mass moves twice as far as the smaller mass.)

2. Formula's Used.
F = ma, W = Mg.

3. The attempt at a solution
Hi,
I need someone to check my answers to this problem. I feel pretty strongly that my answers are correct but they differ slightly from those in my text. Your help would be VERY appreciated. I've exhausted my local sources (Extra texts, and Scham's outlines)for another problem like this to confirm my approach, but was not able to find any. I would feel a whole better if someone else confirmed my answers.
I found the Tension in the rope to be 11.3N, and the acceleration of the 10kg block to be 1.13 m/s2

2. Apr 27, 2015

### haruspex

Your answer doesn't seem right. If the tension is 11N then the net force on the 3k mass is 30-22=8 N downwards. That makes its acceleration roughly double that of the 10k mass. Reread the hint.

3. Apr 27, 2015

### SpacemanRich

I'm sure my answer is pretty close. They give the answer as 13.7N and 1.37 m/s2. Also I found the acceleration for the 10kg mass to be 2 times as fast as the 3kg mass. (2ax = ay.) That is in line with there 2x = y hint.

4. Apr 27, 2015

### haruspex

Your answer may seem close to the given answer, but it makes a big difference to the net force on the 3k block. Your 11.3N gives 3*9.8-11.3*2=6.8; 3*9.8-13.7*2=2.

5. Apr 27, 2015

### SpacemanRich

Ok, I'll post a scan of my work as soon as I can get it scanned in. That will most likely be sometime tomorrow.

6. Apr 28, 2015

### haruspex

Scanning is ok for printed matter, such as textbooks, and your own diagrams, but for working it is much preferred that you take the trouble to type it in. It might take you a little more time, but it saves time for everyone reading it, and makes it much easier to reference specific steps when commenting.

7. Apr 28, 2015

### SpacemanRich

Ok, Thanks for the information. I'll do that in the future. I have my work scanned already. My work equations are numbered for reference. That should help this time.
Thanks for taking a look.

8. Apr 28, 2015

### haruspex

As I hinted in post #2, it's your eqn 3 that's wrong. Reread the hint carefully (but you shouldn't need the hint since you can work this out from the diagram).

9. Apr 28, 2015

### SpacemanRich

From the diagram?? Really, I never would have guessed that. I'll take another look and see what I can see.
Just to check, if I can find the mistake in my eqn 3, will I get the answer the book has?? (13.7N, and 1.37m/s2)
Also I'm glad my FBDs are ok. I thought that may be the source of my error.
Thanks.

10. Apr 28, 2015

### haruspex

yes.

11. Apr 29, 2015

### SpacemanRich

Ok. I have seen the error! Boy do I feel silly.

My equation 3 should be ay = 1/2 ax

I swear, I think my reading comprehension is just off sometimes.

Thanks a lot for the help, again. It is appreciated.