Homework Statement
Let f be twice differentiable with f(0)=6, f(1)=5, f'(1)=2
Evaluate the integral \int_0^{1}x f''(x) dx
Homework Equations
\int uv' dx = uv = \int u'v dx
The Attempt at a Solution
u = x and v' = f''(x)
so
u' = 1dx and v = f'(x)
so
xf'(x) -...
geez this problem is pwning me lol.
so we go...
g(x)x^2 - \int_0^{10} 2xg(x)dx
(2.3)(0) - 2(0)(2.3) = 0, for x=0
(3.1)(4) - 2(2)(3.1) = 0, for x=2
(4.1)(16) - 2(4)(4.1) = 54.4, for x=4
(5.5)(36) - 2(6)(5.5) = 132, for x=6
...and so on...
calculate area under (connected) points (0,0)...
\int_0^{10} 2xg(x)dx
when x= 0, 2xg(x) = 0
x=2, 2xg(x) = 2(2)(3.1) = 12.4
x=4, 2xg(x) = ... = 32.8
x=6, 2xg(x) = ... = 66
x=8, 2xg(x) = ... = 94.4
x=10, 2xg(x) = ... = 122
connect thesse and estimate area under from 0 to 10?
makes sense, but is there any other way to solve the problem?
Homework Statement
Estimate \int_{0}^{10} f(x) g'(x) dx for f(x) = x^{2}
and g has the values in the following table.
\begin{array}{l | c|c|c|c|c|c |}
\hline
\hline g&0&2&4&6&8&10\\
\hline g(x)&2.3&3.1&4.1&5.5&5.9&6.1\\
\hline
\end{array}...
Thats where I am confused. is it 7 units south and 20 east, both starting at the flagpole (origin)? or 7 south from the 50 meter mark, and 20 east from the 70m mark?
the wording on this problem is pwning me. lol
I see the point 1 to point 2 thing now, arrow points northwest.
the one i drew before posting here went in the opposite direction (northeast) my point 2 was 7 inches right above where my 5 inch (east) mark was, and i drew an arrow from the flagpole to that. oops. thanks for clarifying that...
I'm stuck at part b on this problem. I've been working at it for an hour at least! lol
Homework Statement
At one instant a bicyclist is 50 m due east of a park's flagpole, going due south with a speed of 7 m/s. Then, 24 s later, the cyclist is 70 m due north of the flagpole, going due...
Hello everyone. I am stumped here with this problem, i feel like it should be fairly simple but i can't seem to figure it out.
Homework Statement
If the acceleration for a given object is given by the function:
a(t) = +(3 m/s^3) · t
(Note: units are included in the eqn, so if [t]=s...