Recent content by speeddman

(-84/9) m/s^2 Thanks for everything by the way! is that right?

(-84/9) m/s^2 thank you so much by the way for everything! is that right?

second derivative? s''(t)=(-28/9)t^1/3

no it doesnt. 1.3333333333333root of 81 = 27s

well s'(t)=189-7/3t^4/3 0=189-7/3t^4/3 -189/(-7/3)=t^4/3 81=t^4/3 4/3root of 81= t t=0.92448s does that make sense?

81=t^4/3 so t=0.92448s so it takes 0.92448s for the plane to stop. now for to find the deceleration at an instantaneous pnt i have to take second derivative?

...0?

***distance/time

the derivative would represent the deceleration wouldn't it? because the function represents the time.

@rock.freak667 well i don't know wouldn't taking the derivative help me find how long it takes to stop?

Homework Statement When an F-18 jet lands on the runway, it's position is defined by s(t)=189t-t^7/3 meters after t seconds calculate the braking time calculate the deceleration when the jet stops ( i think she means immediately before?) Homework Equations derivative The...

Thank you! i understand it now!

thank you all so very much! every bit has helped me a lot. i have a question however in regards to the standpipe approach. With reference to bobS' picture, wouldn't that trapped air at the top prevent any water from entering via the standpipe?

thank you. i am using it for a grade 12 physics project. we are just testing different things with water and pressure. just to make myself clear i have included a picture of our design. I'm not sure how a stand pipe will work. i think I am just confused though... the issue is that when i am...

sorry i am not familiar with standpipes... how do they work. I do not have a gauge to mesure the pressure in the tank. There is quite a bit of pressure, but no more than you can get with 4 or 5 pumps with a bike pump for example. Sorry i am not very "experienced" when it comes to pressure and...