Recent content by sphykik

im sorry, i don't think we have covered that yet in class. i tried to look it up online, but I am not really having any luck. is there any other way to solve?

can someone explain where to go from here? thanks

so it would just be d = vt 6.4 = v(.88) = 7.27 m/s ? thanks

so, using d= vt + (5.)(a)(t*t) <---- that's t squared, sorry :) i did 3.8 = (0)(t) + (.5)(9.8)(t*t) and found t to be be .88s then i did 6.4 = v(.88) + (.5)(9.8)(.88) and got v to be 2.97m/s so that means that the skater will have to be going 2.97m/s. it this correct so far?

Homework Statement You are planning a stunt to be used in an ice skating show. For this stunt a skater will skate down a frictionless ice ramp that is inclined at an angle of 15° above the horizontal. At the bottom of the ramp, there is a short horizontal section that ends in an abrupt drop...

maybe i didnt provide enough info... i found the weight in Newtons for the 5.1kg weight to be 49.98N, and 32.34N for the 3.3kg weight. I subtracted and got 17.64N. I did F=MA, with F being 17.64, m being 8.4 (or 5.1+3.3) and found a to be 2.1. Now I can't seem to find out how to do the tension...

Homework Statement In the figure below (part a), two blocks are connected by a lightweight, flexible cord that passes over a frictionless pulley. (a) If m1 = 3.3 kg and m2 = 5.1 kg, what are the accelerations of each block? (b) What is the tension in the cord? Homework Equations...

Thanks, I got an answer of 28, and it is correct!

[SOLVED] Velocity Problem Homework Statement A motor scooter travels east at a speed of 12 m/s. The driver then reverses direction and heads west at 16 m/s. What was the change in velocity of the scooter? Homework Equations The Attempt at a Solution Looking at this problem...

THANK YOU SO MUCH! YOU ARE GODLY! thanks so much for all of the help! I got both parts right! WWOOOOOOHOOOO!

would you have T(cos57.9)+23.52, the 23.52 being (2.4)(9.8) to account for gravity?

wouldn't it be F-T cos(57.9) = 0 for the vertical direction?

so if force equals mass * acceleration, than the force would be zero, wouldn't it?

im sorry, but i don't think we went over this in class, i can't find reference to it in the book either. could you explain? sorry to be so stupid :(

so x=T(sin57.9) and y=T(cos57.9)