Recent content by SpicyQ

Ff= mu*n sum of Fx = -Ff + F sum of Fy = N+-w N= w w=mg therefore Ff = mu*m*g sum Fx = mu*m*g+F work done on a spring = (1/2)kx2^2-(1/2)kx1^2 i'm stuck after i plug my equations in.

-------------------------------------------------------------------------------- An object of mass m is traveling on a horizontal surface. There is a coefficient of kinetic friction mu between the object and the surface. The object has speed v when it reaches x=0 and encounters a spring. The...

Please Help! :cry: :bugeye:

Losing Cargo. A box of mass rests on the flat floor of a truck. The coefficients of friction between the box and floor are and . The truck stops at a stop sign and then starts to move with an acceleration of a a) if the box is a distance x from the rear of truck starts, how much time...

thanks.. u were right in ur analysis.. values for m1, m2, a1, and a2 were not given. the only given # is angle teta = pi/2. i'll try and attach a pic here.. thanks

(sorry i can't put up a pic, i'll try my best) imagine a rt angle triangle... (the inclined plane) the block is resting on the hypotenous and the second block is attached on the "leg" with the rope holding both blocks... the question says that imagine the block is on a vertical plane...

help please :cry:

hi i have a question: if you have 2 blocks on a vertical inclined plane... ( with angle teta = pi/2) what would m1 be equal to for a1 and a2 to be = 0 (the answer should be in terms of some or all of the variables of m2 and g) thanks

hi there... im new to this site.. sorry i can't help you w/ that problem... maybe you can help me with a simple question i have?