Recent content by spikefreeman

Great, thanks a lot, that was very helpful.

right, and then solve for v1, and then use mgh. Is that it?

I meant to say, I plug v1 in as sqrt(2gh) and set the v2 as zeroes...

kk, so i just v1o in set the v2 as zeroes and i should be able to find v1. Is that it? For part two I will check in the book., Thanks for you help.

ok that makes more sense. So v2 and v2o are zero. so v1o = Sqrt(2gh) and v1 is solved using mv=mv?

v1o = 0 right? because its dropped from rest. That means that v2o = sqrt(2gh) and that v2 is 0 because it is the maximum of the bounce. Problem 2, that was a typo. It recoils at 1/3 of the incident speed. Sorry about that.

Object 1 is the ball and object 2 is the steel plate. But I have speeds all for object one. O v1o l l l l V v2o ------ The o at the top is the ball and the l and v are an arrow, then the dashes are the steel plate. Then the V1 and V2 are the coresponding speeds except after the collision on...

v1o and v2o are the speeds before the collision, v1o at the top and v2o at the bottom. v1 is speed after collision and v2 is speed at max height after collision. So v1o and v2 are zero, and v2o is sqrt(2gh). Is any of that right? I'm not really sure what you mean by what is -1/3V. Its a...

Homework Statement Problem 1: The coefficient of restitution for steel colliding with steel is 0.95. If steel is dropped from a height ho above steel plate, to what height will the ball rebound. Problem 2: in an elastic head on collision with a stationary target particle, a moving particle...