Recent content by spooky01

Gotcha, that's simple! I was over thinking it. Thank you oh mighty chemistry guy. So in my above equation Ks0 = yMn2+[Mn2+] yCO32-[CO32-], can Ksp be put in for Ks0? 2.2x10^-11 = [Mn2+] (10^-6M) 2.2x10^-5 = [Mn2+]

Ohh I see what you're saying not, Ksp is 2.2 x 10-11.

Ksp = [Mn2+][CO32-] Ksp = [x][x] x= 10-6M Ksp = (10^-6M)(10^-6M) Ksp = 1.0x10^-12 Is this right?

Then an ICE table should be used? Something like this? ____________MnCO3 (s)__________Mn2+ (aq)________CO32- (aq) Initial___________solid______________0_______________10-6M Change__________-x_______________+x__________________+x Equilibrium______-x_______________+x______________10-6M + x

Maybe I'm just not understanding what the problem means. Does it mean if [CO32-] is 10-6M and the ratio of CO32- to Mn2+ is 1:1 in the chemical equation then [Mn2+] is also 10-6M? Is this how others are interpreting the problem?

Homework Statement compare the Ks0 values of MnCO3(s) in fresh water (I=0) and in estuarine waters (I=0.08) at 25°C. If each of the waters contained a concentration of CO32- equal to 10-6M and MnCO3(s) controls the Mn solubility, what is the Mn2+ concentration in each water? What is the Mn2+...

Got it. Henry's law worked! temp 7°C ln(kHT/kH25) = (ΔH°/R)(1/298 – 1/T) ln(kHT/1.26x10-3mol/Latm)=(-11.71kJ/mol/8.314x10-3kJ/molK)(1/298–1/280) ln(kHT/1.26x10-3mol/Latm) = 3.04x10-1 e ln(kHT/1.26x10-3mol/Latm) = e3.04x10-1 kHT/1.26x10-3mol/L atm = 1.36 kHT = 1.71x10-3 mol/L atmC =...

K is for concentration. So if I use Henry's law, Henry's coefficient for O2 at 25 degrees celsius is 1.3×10−3 mol L/atm. How can I adjust Henry's coefficient to work at 7 degrees celsius? Thanks for the help!

Ok I'll simplify it a bit. All I need is how to calculate the equilibrium dissolved oxygen concentration for 7 degrees celsius if PO2 = 21% (this means that if atmospheric pressure is 1 atm then O2 pressure is 21% of that). K was previously found to be 1.813x10-3 at 7 degrees celsius. My...

Homework Statement 1. Calculate the equilibrium dissolved oxygen concentration for each temperature if PO2 = 21% (this means that if atmospheric pressure is 1 atm then O2 pressure is 21% of that) Homework Equations K19.8/RT = Kp PV=nRT The Attempt at a Solution K19.8/RT = Kp K19.8 =...