Recent content by squigley5

Solved: Since BEFD is a square and ABD is a right isosceles triangle, segments DB, BE, EF and FD are congruent. Since ABD is a right isosceles triangle AD is congruent with BD, therefore AD is congruent with FD and their sum is equal to AF. Since we now can mathematically calculate FD and AD...

Thanks for the heads up. Took so long to get it all posted I missed the dropped characters. Fixed it.

Work Continued [FONT=Times New Roman]ForParallelogram EGKH Statement Reason [FONT=Times New Roman]EGKH is a parallelogram Given m HK = [FONT=Times New Roman]√[FONT=Times New...

Work Continued [FONT=Times New Roman]For▲[FONT=Times New Roman]BCG Statement Reason ▲[FONT=Times New Roman]BCG is a right isosceles triangle, [FONT=Times New Roman]m∠BCG = 90° Given and...

Here is the work I have completed, the cells that mention the midpoint construction are the ones that are causing the problem I believe, but I cannot figure a different way to justify the lengths. [FONT=Times New Roman]For▲[FONT=Times New Roman]AFJand [FONT=Times New Roman]▲JFK...

I have looked at the threads posted by others who were working on what seems to be the same task. I have correctly determined all the lengths and angles as the task requires, however am struggling to justify the lengths geometrically, without constructing any midpoints or additional...