I have been trying to find an answer to this problem for some time. So I was hoping the community might be able to point me in the right direct.
https://drive.google.com/open?id=1Y2hYkRG94whLroK20Zmce07jslyRL3zZ
I couldn't get the image to load. So above is a link to an image of the problem...
So I made a little program to try to solve this and in doing so I realized a few things and started doing some reading to see if I could find more answers.
I need to explain a few things. All I did with the below expression is factor the R vector and defined P as the percent tolerance matrix...
MFB is this more in line with the idea of "Take the derivatives multiplied by the resistances to get a more meaningful quantity to minimize"
Most resistors tolerances are in a +/-% of the value of the resistor.
G_d\left(\left(I+P\right)\vec R\right) \approx G_d\left(\vec R\right)+\nabla_\vec R...
A linear approximation for the differential gain and the tolerance could be written as such:
G_d\left(\vec R+\vec T\right) \approx G_d\left(\vec R\right)+\nabla_\vec R G_d\left(\vec R\right) \cdot \vec T
If we assume the tolerances are all equal we would get the following:
G_d\left(\vec...
I didn't want to list all of the partial derivatives. There would we 10 equations in all and only 4 variables. This would be an over determined system.
##G_d = 1##
##G_s = 0##
##min\left(\frac {\partial G_d} {\partial R_1}\right)##
##min\left(\frac {\partial G_d} {\partial R_2}\right)##...
The gains of an OP-AMP are listed below:
G_d = (R_1*R_4+R_2*R_3+2*R_2*R_4)/(2*R_1*(R_3+R_4))
G_s = (R_1*R_4-R_2*R_3)/(R_1*(R_3+R_4))
\frac {\partial G_d} {\partial R_1} = -R_2*(R_3+2*R_4)/(2*R_1^2*(R_3+R_4))
My questions is...
Is there a mathematical perform the following:
Differential gain...
I am an engineer. I memorized the integral form of the conservation laws (fluids). I memorized the integral form of maxwells equations (electronics). I understand that summation of force equals change in momentum. I understand that a closed geometric loop sums to zero. Force balance doesn't...
If you know the velocity of an object as a function of position Can you use a uniform distribution over one period and the object velocity to perform a change of variables for the positional probability.
Example.
X(t)=Asin(wt)
V(t)=Awcos(wt)
V(X)=+-Aw(1-(X/A)^2)^(1/2)
P(t)=1/T
T=Period
Change...
One question... Can the differential amplifier back feed noise from either PWM signal into the other. I wouldn't want current feedback into the controller/computer. If so would a diode help with this or would it create other issues.
Well I know this is an old post. But I did come up with a way to directly control a dc motor with two pwm signals without the use of a bridge.
1. Setup two PWM signals with the same period and amplitude of Vmax
2. Pass both signals thru a differential amplifier to get a differential signal...
Each equation has its own period. That is not an issue, there is also a sequence of times where both equations simultaneously repeat.
x(t+Tx)=x(t)
y(t+Ty)=y(t)
x(t+Ts)=x(t)
y(t+Ts)=y(t)
I am looks for Ts a time that satisfies both equations simultaneously.
Sorry for the unclear question.