Recent content by SSj5NOTHARSH

whoops, let's try this again. . . . f(y,z) = n(y3 + z3) + a; For y = 0, and positive y; For x, 0 to h f(y,z) = n(-y3 - z3) - a; For negative y; For x, -h to 0 f(y,z) = n(y3 - z3) - a; For negative y; For x, -h to 0 f(y,z) = n(-y3 + z3) + a; For y = 0, and positive y; For x, 0 to h f(y,z)...

i was looking for the same thing today and came across this question what i came up with was a combination of 8 functions for a 3d representation, although i am not certain if they are correct. also of note is that this is for it laying on its side. anyway, here goes: x = y3 + z3 + 1, For...