I attempted..
Ksp=1.8x10^-10
1.8x10^-10=[Ag][Cl]
[Ag]=[Cl]=√1.8x10^-10
=1.3x10^-5M
So I got the solubility for both elements.. do I just add since AgCl⇔Ag+Cl?
CaF2⇔Ca+2F.
Many places state that Ksp=[Ca][2F]^2; Ksp=[x]*[2x]^2.
I thought the coefficient go into Ksp equation as an exponent. So, Ksp=[Ca][F]^2.
Can anyone explain which is correct, or why [2F]^2 (if that's the correct one)?
Homework Statement
Calculate the solubility of silver chloride at 25℃.
Ksp of silver chloride at 25℃=1.8x10^-10
Homework Equations
AgCl⇔Ag+Cl (I believe)
So, Ksp=[Ag][Cl]
The Attempt at a Solution
All I know is the Ksp of silver chloride at that temperature. I have no idea what to...
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