Recent content by Stang289GT

Hmmm...okay. (there's a figure that goes along with this, but I can't upload it...) Plugging in the maximum x=(a*sqrt(2))/2 value into equation 2 you get: Emax=(k_e*Q*((a*sqrt(2))/2))/(((a*sqrt(2))/2)^2 + a^2)^(3/2) simplifying this, I think it's supposed to be: Emax=(k_e*Q*sqrt(2))/6a...

Homework Statement Determine both the location and the maximum magnitude Emax of the electric field along the axis of a uniformly charged ring. (Use epsilon_0 for ε0, Q, and a as necessary.) Homework Equations 1) dE= (ke)dq/r^2cos(theta) cos(theta)= x/r...