Hmmm...okay.
(there's a figure that goes along with this, but I can't upload it...)
Plugging in the maximum x=(a*sqrt(2))/2 value into equation 2 you get:
Emax=(k_e*Q*((a*sqrt(2))/2))/(((a*sqrt(2))/2)^2 + a^2)^(3/2)
simplifying this, I think it's supposed to be:
Emax=(k_e*Q*sqrt(2))/6a...
Homework Statement
Determine both the location and the maximum magnitude Emax of the electric field along the axis of a uniformly charged ring. (Use epsilon_0 for ε0, Q, and a as necessary.)
Homework Equations
1) dE= (ke)dq/r^2cos(theta)
cos(theta)= x/r...