leave answer with variables?
Hi
So this problem is for first year university calculus.
I got confused about the derivative... i do know how to do derivates... too much calculus in one day i guess.
So from the steps shown, I followed them and they seem pretty clear.
So do I not...
Hello
i need help with a question, other people tried to help me, i just cannot get it! its driving me crazy
Two positive numbers have sum n. What is the smallest value possible for the sum of their squares?
so i have n=x+y
x>0 y>0
y=n-x
we want to minimize S S=x^2+y^2...
OK
So laws of logarithms:
1) log[SIZE="1"]a1=0
2)log[SIZE="1"]a(xy)=log[SIZE="1"]ax+log[SIZE="1"]ay
3) log[SIZE="1"]a (1/x)=-log[SIZE="1"]ax
4) log[SIZE="1"]a(x/y)=log[SIZE="1"]ax-log[SIZE="1"]ay
5)log[SIZE="1"]a(x^y)=ylog[SIZE="1"]ax
6)log[SIZE="1"]ax=log[SIZE="1"]bx/log[SIZE="1"]ba...
my question is simplify:
log[SIZE="1"]pie(1-cosx)+log[SIZE="1"]pie(1+cosx)-2log[SIZE="1"]pie sinx (i don't know how to make the pie symbol)
i thought it was going to be
log[SIZE="1"]pie-log[SIZE="1"]piecosx+log[SIZE="1"]pie+log[SIZE="1"]piecosx-2log[SIZE="1"]piesinx
=...
still a bit confused
it was the first one, the one you were working out.
since your multiplying ln2 by (x^2-3) wouldn't it be 3 ln2?
So from ln(2)x2 - ln(4)x - 2ln(3) = 0
you get (x-6)(x+2) so x=6, x=-2.
I tried putting this numbers in the original but it doesn't work out, what am I doing...
solve the equation:
2^x^2-3=4^x (2 to the power of x squared - 3)
i can't get it to work
ln2^x^2 - 3=ln4^x
(x^2 -3) ln (2)=xln(4)
i know it'd be -3(ln2)=xln4... but i don't know what to do with x^2 part.
i did other questions like this but with 5^2x and 3^1+x, what do I do with the...