Recent content by StasKO

Homework Statement A coaxial cable with inner radius a and outer radius b lies on the z-axis (such that the cable's axis merges with the z-axis). its length (along z-axis) is L. at z=-L there are voltage sources that are distributed uniformly connecting the inner wire to the outer one. at...

okay ill ponder on this a bit more on my own.. thank you very much for your help and the extremely fast responses!

so why in the inner edge of the outer sphere the distribution is non uniform? its the same conductor having the same conductivity. shouldn't it be uniform just with the total charge on that edge the same as the total charge in the inner sphere?

well ill take it as it is but it still puzzles me how in a conductor one edge has non uniform distribution and at the outer edge the distribution is "suddenly" uniform. what prevents it from being also non uniform?

I understand that inside the volume of the outer sphere the potential is constant and equals to the potential at r=R2. but what is this potential? In the solution that was given to us, the teacher just applied gauss's law in integral form to the region r>R2, found the electric field and then...

Homework Statement A spherical shell of radius R0 has a non-uniform surface charge density: η=η0*cos(2θ), where θ is the angle measured from the positive z axis and η0 is a constant. This shell is inserted into another spherical shell (this one has a volume) with its inner lip at radius R1...

ohh ok... now i got it lol anyways i think now i have enough info and tools to solve this experiment.. now I am going to sit on my as* and finish this... thank you so much for the brain storming.. it is much appreciated (be ware i might be back for more questions lol)

because it should be derived from some kind of equation i think.. can i say that the period T is proportional to the distance r so that T=kr for some constant k? then find k by building a linear graph (y=T, x=r) and determining k from the slope of that graph.. then plug T=kr into the time...

im still not sure i really understand your solution... on what basis do you say that the ratio between two distances is equal to the ratio between two (corresponding) accelerations?

by 'm' you mean a coefficient and not mass right? and instead the a's i can put (magnetic force)/(mass of iron) right? i had a thought and not sure if its true.. is it possibe that instead of the length l of the pendulum i'll put the total length - pendulum + distance to magnet?

well.. the thing is that the pendulum's length is not changing.. its the magnet that changes its position (only vertically).. the magnet is on a jack.. it might help to tell you that we had a similar experiment but with no magnet.. only pendulum.. so we measured the period T and length l... we...

no.. i didnt receive any info about the magnet itself.. i know that i need (eventually) build a graph in excel.. from the slope of that graph i need to extract the magnetic force.. so if the graph equation is y=ax+b then y = T^2 and x should be the distance (something along this line).. a, which...

first of all thank you for your welcome.. this forums helped me a lot.. back to the issue.. so as i understand it, i need to replace the g in the equation to a general 'a' which represents the total acceleration downwards. this 'a' is the sum of g and the acceleration due to the magnet...

Homework Statement this is an experiment from lab.. i have pendulum - mass (iron) hanging from a massless cord. under the mass there is a magnet. the movement of the pendulum is in a small angle. i repeat the experiment 5 times - each time in a different distance between the iron mass and...