Recent content by Steel Worker

Using the equation P2 = PI + 1/2(rho)(V1^2-V2^2)... If the (5) inlet pipes and the (1) outlet pipe have the same diameter, then P1 = P2?

10-4, I understand

Why wouldn't I multiply each of the supply pressures by 5 if they are all separate from one another contributing to the flow of the larger pipe?

Q1 = 4.5 GPM, There are 5 inlet pipes of this same flow rate. Converting Q1 to cu.in/sec = 4.5 Gallon/min x (1min/60sec) x (0.1337 cu.ft/1 gallon) x (1728 cu.in/1 cu.ft) = 17.32 cu.in/sec. To get the Velocity, V=Q/A, which is 17.32 cu.in/sec/0.141 sq.in = 123.3 in/sec. I found the velocity...

Neglecting friction and head losses, I elected to use Bernoulli's equation: P1 + p(V1^2)/2 = P2 + p(V2^2) Since I know Q1 = 5(4.5 GPM) = Q2 = 22.5 GPM or 86.6 in^3/sec ID of 3/8" Sch. 80 pipe = 0.423 inch A1 = 0.141 in^2 A2 = 1.77 in^2 (ID = 1.5 inch) Q=AV, V=Q/A, V1 = 123.4...

There are (5) 3/8" diameter pipes supplying water at 3500 psi and 4.5 GPM each from 5 separate pumps. These (5) lines connect to a main 1.5" diameter pipe. What is the water pressure in the main pipe?