Recent content by steelers2147

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    Improper Integrals: Solving Homework Statement

    So the integral is equal to inverse sine of x. So evaluated from 0 to 1 we have that it is equal to pi/2 <2?
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    Proving the Fundamental Theorem of Calculus Twice

    Homework Statement Complete the proof by using the Fundamental Theorem of Calculus TWICE to establish \int_c^d(\int_a^b f _{x}(x,y)dx)dy=...=\int_a^b(\int_{c}^{d}f_{x}(x,y) dy)dx Homework Equations I know that the FTC states that if g(x)=\int_a^x(f), then g'=f The Attempt at a...
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    Improper Integrals: Solving Homework Statement

    By the Fundamental Theorem of Calculus, if I(a) = \int_0^a \frac{1}{\sqrt{1-x^2}}\ dx, then I'(a)=1/(sqrt{1-x^2}. Then, since 0<x<1, we see that sqrt(1-x^2)>0. Thus, I is increasing since I'(a) is positive. I'm still not sure how to show that I is bounded by 2...
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    Improper Integrals: Solving Homework Statement

    Homework Statement Suppose 0<a<1. 1) Show that 0<Integral(0 to a)1/(sqrt(1-x^2)<=Integral(0 to a)1/(sqrt(1-x)<=2 2) Show that I(a)=Integral(0 to a)1/(sqrt(1-x^2) is increasing and bounded by 2. 3) Deduce that Integral(0 to 1)1/(sqrt(1-x^2) exists and has an improper integral...
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