The compound is asymmetrical. The methyl group is an electron-releasing group which stabilizes the intermediate formed, in this case the ionized azirine (formed upon removal of the Cl leaving group). Thus, the 3rd resonance structure is more stable than the first and second structures...
Now I'm thinking that the methyl on the bottom ring exerts an effect on the entire compound forcing the propyl chain to attach to the bottom carbon of the chloroazirine (demonstrated in the major product).
Homework Statement
The Attempt at a Solution
I want to recognize the Cl as a good leaving group. After leaving, I get the ionized form of the chloroazirine reactant. Then, I want to draw some resonance structures to move the charge around the ring.
I do not understand the...