My professor wrote ln(P)=(-Hvap/R)*(1/T)
on my paper then I just solved for T.
Is this is not the correct formula to find the normal boiling point? What is? Oh, and does my Hvap look ok?
Thanks for all of the help. I appreciate it.
Stephen
if both pressures are the same then ln(P2/P1) in the formula ln(P2/P1)=(-Hvap/R)*((1/T2)-(1/T1)) would be zero and when finding the temperature T=(-hvap/R)*(1/ln(P)) ln(P) would equal ln(1) thus there would be a zero in the denominator. So how would that work?
Thanks for the help.
Stephen
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