Recent content by SteveS

I'm actually wondering about this point. At when the masses are balanced m1 - m2 = 0, acceleration should also be 0. However, I'm not totally sure why the graph of mine shows a y-intercept greater than zero. Does it have to do with error introduced by margins of error in my measurements?

I'm doing the same lab and he is making a mistake in the formula. The formula given in the lab manual is: (m1 - m2)g = (m1 + m2 + I/R^2) a This maybe a source of his problem. In my lab, I had one of those folding metal clasp type paper clips attached to each end of a piece of dental floss...

I didn't put it in the post I made before but the ∑T equation is: ΣT = T1*(0) + T2(1.6 m) - (45kg)(9.80 m/s^2)(0.91m) distances are all from T1 since it's the pivot point. This let's you zero out T1 and find for the unknown T2.

Hey Brendan, lucky I was just checking something else out on here when you asked. I used 1.6m for the torque because T1 is the pivot point so from T1 to T2 is 1.6m.

Thanks and you too. Just finishing up organic chemistry and I'm done for the summer... 9 labs to write :(

Yes, the exam questions are easier thank goodness. They are similar but they give you a lot more figures so it's a lot easier math as it is more just about using the formulas properly.

Yes, I am also a student with Athabasca University. I wrote my final exam on the 17th of April. I managed to get a pretty good final grade. The help here was a big asset. Tutor questions take too long and they can't really say much about assignment questions. I was amazed at the gap between the...

You could have also saved yourself the need to use the quadratic equation. If you have 6v^2-8v = 0 you can then just factor out v and have v(6v-8) = 0 Looking at this equation you can make the relation true if v = 0 because then 0 times what's in the brackets will be zero. then you can also...

Ok. Sorry to those who have been trying to help me. I'm an accountant who graduated from university the first time about 12 years ago. I'm now a microbiology major and haven't had to use trig in a very very long time, but I have to take this one physics class in order to graduate. I took a...

I'm not sure what that means or how that even helps. me. never mind no need for more replies. I can't waste any more time on this question.

The equation u1^2 = v1^2 + v2^2 is the conservation of energy equation I already posted. The other equation you posted I do not know how to derive and the rest does not follow. Never mind I'm done with this crap. Pretty frustrated.

I'm sorry i don't mean to be rude , but tell me something I've not already said... I know. I don't know how to use it. I can't ever get to a point where I can actually use the relation. In my circular calculations for the last three days I haven't been able to reduce anything to the point where...

I have done so already which is what leads to the three equations that I laid out at the beginning.

In my previous post I mentioned I was aware of the relation cos^2 θ + sin ^2 θ = 1... What I'm not sure is how you got to that equation you posted.

Honestly I've got four pages of scribbles and I'm really turned around. I'm not sure what to do anymore. The last thing I did was I rearranged the x component equation to v1' = va - v2' * Cos θ / Cos 30 I then substituted this into the energy equation which i got down to Cos 30 = Cos θ is...