why are they all squared when the original equation was v = r\omega? where does the squaring come from?
oh, omega is sqaured in the conservation equation I set up so you just moved it into the other equation to show an easy variable switch.
Ah, ok I think I see what you are saying and I see how the relationship brings in the r which something I have to have in my final equation.
So I have:
MgH = \frac{1}{2}I\omega2 + \frac{1}{2}Mv2
and
\omega= v/r
so
MgH = \frac{1}{2}I\frac{v}{r}2 + \frac{1}{2}Mv2
I don't know if this...
Okay so from this I find that
\bar{L} = \bar{r} x m\bar{v}
and
\bar{\tau} = \bar{r} x m\bar{a}
The difference between the two is the acceleration from the velocity. Acceleration is the derivative of velocity. So it looks like I find the linear momentum first and then since I have that I...
U=MgH \leftarrow since I don't have numbers I can't calculate that. but I know
Ui + Ki = Uf + Kf (assuming no E loss) \leftarrow where Ki is zero and Uf is zero. I can split kf into Krot and Ktrans
so
U + 0 = 0 + Krot + Ktrans
Ktrans = \frac{1}{2}Mv2\leftarrow inserting my vtrans in gives...
Hi guys, I am hoping you can either point me in the right direction here or show me how to do this a bit. the problem is as follows:
"a particle with weight 86.8 N is positioned at r= (8.1t)i - (7.2t-9.4t2)j.
t is in seconds. Find an expression for angular momentum, L and torque, T which act...
Hello there I am really struggling with this and another problem and I was hoping you guys could help me out. The problem is as follows:
"the cylinder shown has a radially-dependent density with mass M and radius R. The cylinder starts from rest and rolls without slipping down the incline...