Recent content by StrangerDanger

Thanks for the welcome :). The only method I can think of when dealing with changing acceleration by breaking it into parts. Each part for every time the value of acceleration changes. I have not yet learned ho to derive very well but I know it exists. As for angle β I am clueless on what to impose.

Homework Statement With this problem I have to get the answer: cosθ = r/L * cosα - √(3)/2 * (1 - r/L) which in other words mean I need to find angle θ with arccos[r/L * cosα - √(3)/2 * (1 - r/L)]. Here's the picture: Lcosθ is the vertical length of the string at its lowest point. rcosα is a...