Recent content by student07

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    Impulse/final velocity question confusion

    yeah I totally missed the subtracting a negative on the RHS that makes more sense now thank you
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    What is the importance of physics in sonography programs?

    Hello Rain welcome to the forums, same issue is happening with me only thing is that I am going for the architecture career but this website has provided me and many others with a lot of help from the community, I'm glad you found it. You will too find it useful good luck in the future :)
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    Impulse/final velocity question confusion

    I uploaded my question below; basically I am confused in part b) where they show that: 50 kgm/s = (5kg)v2 - (5kg)(-4m/s) then they say that 30 kgm/s = 5kg v2, but shouldn't it be 70 kgm/s = 5kg v2? As noted at the beginning of the question North is positive and thus since the cart moves south...
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    Spaceship constant speed problem

    All thanks to you, thanks for not giving up on me lol you were very supportive :)
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    Spaceship constant speed problem

    (43 / 120)^2 = 1-v^2 0.128402777 = 1 - v^2 v^2 = 1 - 0.128402777 v = 0.93 c
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    Spaceship constant speed problem

    So then, √0.023333333 = √(1-V^2) - square root of 1 is 1 and V^2 remains right ? = 0.152752523 = (1-V^2) v^2 = (1 - 0.152752523) v^2 = 0.847247476 v = 0.92 c
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    Spaceship constant speed problem

    I don't know any other way then this people got it this way https://answers.yahoo.com/question/index?qid=20120418090716AApo5pz but I don't get the gamma part...is ok is only a few marks thanks for your help
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    Spaceship constant speed problem

    ok then 2.8 = 120√(1- V^2 ) 2.8 / 120 = √(1- V^2 ) 0.023333333 = √(1- V^2 ) √0.023333333 = (1-V^2) 0.152752523 = (1-V^2) v^2 = (1 - 0.152752523) v^2 = 0.847247476 v = 0.92 c is this correct now?
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    Spaceship constant speed problem

    well 43 m = 120√(1- V^2 / C^2) then, 43 = 120√(1- V^2 ) - c^2 should be canceled like in part a) 43 = 120(1- V) - square root and ^2 should cancel each other 43 / 120 = (1-V) and finally v = 1 - (43/120) = 0.64 c since 0.64 is smaller than 0.70 c that's why I said before that it...
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    Spaceship constant speed problem

    60√(1-0.49) = 42.85 = 43 m = 120√(1- V^2 / C^2) = 0.64 c is what I get now but shouldn't ship b be faster than ship A?
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    Calculating Mass-Energy Conversion in a Nuclear Power Plant

    Since you are here can you also help me with this https://www.physicsforums.com/threads/spaceship-problem.816803/#post-5127239 thank you!
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    Spaceship constant speed problem

    So 43 / 120 = 0.36 0.36 = 120√(1- V^2 / C^2) = 0.99 c I'm still thinking it should be, 120 / 43 = 2.8 2.8 = 120√(1- V^2 / C^2) = 0.98 c
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    Calculating Mass-Energy Conversion in a Nuclear Power Plant

    Omg I am so dumb lol, 60 min = 3600s, 86400 s in a day, 2,592,000 s in 30 days thus, (3 x 10^9 W)(2,592,000 s) / (3 x 10^8 m/s) ^2 = 0.0864 kg
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    Calculating Mass-Energy Conversion in a Nuclear Power Plant

    1 hr = 60 sec, 24 hr = 24 x 60 = 1440 s in a day, 1440 x 30 = 43200 s in 30 days thus, (3 x 10^9 W)(43200 s) / (3 x 10^8 m/s) ^2 = 1.44 x 10^-3 kg
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    Calculating Mass-Energy Conversion in a Nuclear Power Plant

    Homework Statement A nuclear power generating station generates 3 x 10^9 W of power. How much mass does the plant convert into energy in one month (30 days)? Assume that the process is 100% efficient. 2. The attempt at a solution m = E / c^2, E = P x t m = (3 x 10^9 W)(30 days) / (3 x 10^8...
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