Recent content by Subliminal1

Oh, it just clicked... The entire point here is that $$x$$ can be anything, it's the method we use to find $$x$$ that is being assessed. Sorry, I appreciate your patience!

Ok, so as we have to show our working, how would they have come to the conclusion that $$x=1.2$$? Thanks

Sorry, I'm still not following. With my working I've replaced $$x$$ with $$1.2$$, as per our lecturers solution and it does make sense, but I'm unable to figure how the equation was simplified to get it: $$x=1.2$$ $$y=5\left(1.2+3\right)$$ $$y=21$$ $$\frac{21}{5}-3=1.2=x$$ So, I can see...

It's no problem, I appreciate the hospitality here, it helps this forum stand out amongst the others!

Hi, thanks for confirming this for me. Now to ask our lecturer point blank to explain their workings. Any tips on how to do this respectfully? ha, just joking. Funnily enough I was here a few years ago...

Hi, the problem was literally "make $$x$$ the subject:" with a list of equations such as: Q:$$y=x+3$$ A:$$x=y-3$$ Q:$$y=x$$x$$5$$ A:$$x=\frac{y}{5}$$

Hi, we were rearranging formula to make $$x$$ the subject and for one equation our answer was different to our lecturers, but they failed to explain why they were right and we were wrong- if someone could that would be great. The equation with our working: $$y=5\left(x+3\right)$$...

Hi Sudharaka, I'm glad all those years at school actually got through to me - so "that" is what school is for! But seriously, thank you for your reply so soon, it was well explained also. Cheers John/ Sub

Hello, I'd like someone to double check my maths please, it wasn't the greatest at school and that was a few years ago! If I am incorrect could you please tell me the correct answer as well as show me how to apply it so I can figure out similar problems myself. Thanks. Yes, this is about...