Thanks for the reply.
In RHS summation is over all possible q. Could you please clarify the last part of your explanation where you say that it would be true if it is written as FT(LHS) and use a combination of Parsevals theorem and some differentiation property. How do I see that?
Thanks.
I am not able to comprehend this :
/int dx (df(x)/dx)^2 = \sum (q^2 F(q)^2 where F(q) is the Fourier transform of f(x).
Can some one throw light?
thanks.
I wud appreciate if u can just check this out.
http://www.google.co.in/search?q=%22a+vector+is+a+vector+is+a+vector%22&sourceid=mozilla-search&start=0&start=0&ie=utf-8&oe=utf-8&client=firefox&rls=org.mozilla:en-US:unofficial