Recent content by Sunanda

@jim hardy : Thankyou for taking time. It helped. :)

@jim hardy My doubt is still left uncleared. Jishnu tried to answer it, but it didn't help much. Will you tell me how much charge should flow from Earth to plate B, upon earthing so as to nullify its initial potential (of course w.r.t. infinity) which was present due to positively charged plate...

Yeah. Okay :)

Thanks for the video. In the second part of the video, I was wrongly computing E = σ/ε° to be emerging from one plate. E in the Gauss Law is the net electric field present in the gaussian surface, not just the electric field due to charge under consideration.

The line that says 'capacitance of plate B has to increase for sure': Isn't capacitance dependent upon A, d & ɛ ? If it is so, then capacitance of a parallel plate capacitor is dependent upon its geometrical configuration only. So in the relation Q = C × V , Q changes as a function of V between...

O yes, you are right. Mistake was all mine. Pardon. Thanks for clarifying. Actually I wrongly built up a concept that if a face of charged plate has charge Q/2 on it, that means it has a surface charge density σ/2 on that particular face, then electric field due to that face will be σ/2ɛ°. Thus...

If the potential of a single charged plate w.r.t. infinity is complicated to calculate, then leave the calculations. My confusion is only related to determining how much charge should flow from Earth to plate B, upon earthing so as to nullify its initial potential (of course w.r.t. infinity)...

Here's the video lecture of the teacher I mentioned about. His accent might be a bit tough to understand. This lecture is about earthing of a system of parallel metal plates. I asked this question because I was wondering what was the positive potential at plate B which upon earthing gets...

Assuming its potential w.r.t. infinity (in the beginning) was zero, and assuming Earth's potential is zero, I request you to answer now. Thanks in advance :)

A teacher in a video lecture stated that assuming, no earthing is done: Potential of plate B will be zero on account of charges induced on it (i.e. -Q/2 and +Q/2). But Potential of plate B will be positive on account of charge +Q on nearby plate A. Thus, net potential of plate B will be positive...

I have two isolated plates A and B, kept parallel to each other. Now I give charge +Q to the plate A, it will redistribute itself as +Q/2 on the outer plate A and + Q/2 on the inner plate A. Right? Now this will induce charge -Q/2 on the inner plate B and +Q/2 charge on the outer plate B...

Besides the people who have taken their time out to try clarifying my doubt here, I would like to thank Doc Al also who explained things quite well on a similar thread given below https://www.physicsforums.com/threads/electric-potential-energy-due-to-a-point-charge.475543/

My doubts have been cleared and therefore, I have re-written down notes of complete derivation compiled into 3 pages, which I am going to attach as .jpg files. Page numbering is done at the top of pages :)

Upon re-reading you explanations, including explanations on other threads, finally my most of the doubts have got cleared including the ones mentioned in the previous two posts. So you needn't clarify them now ☺️. Thankyou for your time :) But there's just one doubt left related to this thread...

If I compare it with V= mgh, or gravity. If I carry book up from the floor against the gravitational force, the work done by me on the book will be positive. Because both the force and displacement will be in same direction. Right? Here also, while writing dW= F.dr' I assumed my infinitesimal...