Recent content by suyoon

yea.. i get the fact that \frac{\partial u(L,t)}{\partial x} = 0 , but what's the boundary condition in order to satisfy this? and the normal modes?

I think i made the question a little bit unclear. what i meant by no horizontal movement is that the string may move up and down at just one end while the other end is still fixed. so for the boundary condition, u(0,t) would still be 0, while u(L,t) will no longer be zero.

Waves on a finite string; normal modes Let's say there is a string that is tied down at its both ends (at x=0 and x=L). In order to satisfy the wave equation: a2u/at2=c2*a2u/ax2, the boundary conditions must be that: u(0,t)=u(L,t)=0 for all times t, where u(x,t) denotes the displacement of...

A string with one end fixed as U(x=0,t)=0. The other end is attached to a massless ring which moves frictionlessly along a rod at x=L a) Explain the boundary condition at x=L should be d/dx U(x,t) = 0. b) Find the normal modes for the wave equation d2/dt2 U(x,t) = c2 * d2/dx2 U(x,t) with the...